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500.0 mL of 0.140 M NaOH is added to 555 mL of 0.250 M weak acid (Ka = 5.01 × 10-5). What is the pH of the resulting buffer?

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  • 500.0 mL of 0.140 M NaOH is added to 555 mL of 0.250 M weak acid (Ka = 5.01 × 10-5). What is the pH of the resulting buffer?


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