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Solve the differential equation (y'')^2 - 2y'' - 2xy' + (y')^2 + x^2 = 0 y'(0) = 1, y(0) = 1/2?

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  • Solve the differential equation (y'')^2 - 2y'' - 2xy' + (y')^2 + x^2 = 0 y'(0) = 1, y(0) = 1/2?


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